Question

Please Please Please....
Solve this question...but only if you know...

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Answer 1

Equation is : (a² - 1)x + a(x² - 1) = a²(x² - x + 1)

=> a²x - x + ax² - a = a²x² - a²x + a

=> a²x - x + ax² - a - a²x² + a²x - a = 0

=> (a - a²)x² + (2a² - 1)x - a² - a = 0

Here, a = (a - a²), b = (2a² - 1), c = (-a² - a)

∴ D = b² - 4ac

  = (2a² - 1)² - 4(a - a²)(-a² - a)

  = 1.

Quadratic Equation Formula :

x = -b ± √D/2a

  = -(2a² + 1) ± √1/2(a - a²)

x = (a + 1/a) and x = (a/1 - a)

#BeBrainly

Answer 2

Answer:

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