please please prove the above question fast
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=log{a²\bc} +log{b²/ca} +log{c²/ab}
we know that,
loga + logb=logab
Now we have,
=log{a²/bc×b²/ca×c²/ab}
=log1
=log10^0
=0log10 (loga^m=mloga)
=0×1 {log(basea) a=1}
=0
we know that,
loga + logb=logab
Now we have,
=log{a²/bc×b²/ca×c²/ab}
=log1
=log10^0
=0log10 (loga^m=mloga)
=0×1 {log(basea) a=1}
=0
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