Question

Please please solve it

Answer 1

Answer :-

Given that

x + y = 2

1/x + 1/y = 10
or
(y + x)/xy = 10

as because x + y = 2
=> 2 = 10 xy

=> xy = 2/10

now as we know that

$x^3 + y^3$ = $( x + y )^3 - 3xy(x+y)$

=> $x^3 + y^3$ = $(2)^3 - 3× 2/10 (2)$

=> $x^3 + y^3$ = $8 - 1.2$

=> $x^3 + y^3$ = 6.8

Hope it helps you

Answer 2

Answer:

x+y=2

so,x=y-2

putting the value of x in 1/x+1/y=10

1/y-2+1/y=10

y+y-2/(y-2)y=10

2y-2=10(y^2-2y)

2y-2=10y^2-20y

10y^2-22y+2=0

5y^2-11y+1=0

comparing above equation with ax^2+bx+c=0 ,we get

y=2.104987562 or 0.9501243789

when y=2.104987562,x=0.104987562

so,x^3+y^3=9.3262995

when y=0.9501243789,x=-1.049875621

s0,x^3+y^3=-0.2995018656

Step-by-step explanation: