Question

please please solve this...​

Answer 1

Answer:

let x+y be a

3a2-5a+2

3a2-6a+a+2

3a(a+2)+1(a+2)

(3a+1)(a+2)

we put the value of a

so,

(3(x+y)+1)(x+y+2)

so and is (3x+3y+2)(x+y+2)

Answer 2

hey mate :

find here

factor of 3(x+y)²-5(x+y)+2

Answer:

3(x+y)²-5(x+y)+2=0

let

x+y=p

so,

3p²-5p+2=0

3p²-3p-2p+2=0

3p(p-1)-2(p-1)=0

(3p-2)(p-2)=0

so,

put p=x+y

so, will be

[3(x+y)-2][x+y-2]=0

I hopes its helps u

@Abhi.❤❤