please please solve this problem
from number 3 to 6 please
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This is my answer. Hope it helps!
If it did help, please mark my answer as brainliest
If it did help, please mark my answer as brainliest
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Hi there!
Here's the answer:
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3.
Percentage of protein in cereals = 12%
In 14 gm package,
percentage of protein = 12% of 14 = (12/100)× 14 = (3/25) × 14 = 1.68
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4.
Total No of pages = 160
15% of these have pictures
Remaining (100 -15)% = 85% doesn't have pictures
=> No. of pages without pictures = 85% of 160 = (85/100)×160 = 17×8 = 136
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5.
Let x be the total distance covered
12% of x walked
16% of x ran
28% of x rode on scooter
Remaining [100-(12+16+28)]% of x = 44% of x travelled in bus
given x = 50 km then
distance travelled in bus = 44% of x = (44/100)×50 = 22km
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6.
(i)
Out of 20 vehicles, 7 were buses
=> (7/20)×100 = 0.35 × 100 = 35%
(ii)
Total tickets = 400
tickets sold to Sr. citizens = 144
Remaining (400-144) = 256 tickets sold to the rest
Percentage of tickets sold to the Sr. citizens
= (No. of tickets sold to Sr. citizens/No of total tickets) × 100
(144/400)× 100
= 0.36×100
= 36%
Percentage of Tickets sold to the rest
= (No. of tickets sold to the rest/No. of total tickets) × 100
= (216/400)×100
= 0.64×100
= 64%
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7.
Hrs spent in school = 7 1/2 = (15/2) Hrs
Total Hrs in a day = 24 Hrs
percentage of hrs spent in school per day =[(15/2)/24]×100%
= (15/48)×100%
= 37.25%
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8.
% composition = (Ratio of tin to copper) × 100
= (3/5)× 100
= 60%
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9.
Old price = 4₹
New price = 5₹
Change in price = 1₹
4₹ ---> 100%
1₹ -----> (100/4)% = 25%
•°• Required % Increase = 25%
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10
old price = 240₹
New price = 210₹
change in price = (240 - 210) = 30₹
240₹ ----> 100%
30₹-----> (30×100)/240 = (300/24) = 12.5%
•°• Required % Decrease = 12.5%
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
©#£€®$
:)
Hope it helps
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
3.
Percentage of protein in cereals = 12%
In 14 gm package,
percentage of protein = 12% of 14 = (12/100)× 14 = (3/25) × 14 = 1.68
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
4.
Total No of pages = 160
15% of these have pictures
Remaining (100 -15)% = 85% doesn't have pictures
=> No. of pages without pictures = 85% of 160 = (85/100)×160 = 17×8 = 136
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
5.
Let x be the total distance covered
12% of x walked
16% of x ran
28% of x rode on scooter
Remaining [100-(12+16+28)]% of x = 44% of x travelled in bus
given x = 50 km then
distance travelled in bus = 44% of x = (44/100)×50 = 22km
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
6.
(i)
Out of 20 vehicles, 7 were buses
=> (7/20)×100 = 0.35 × 100 = 35%
(ii)
Total tickets = 400
tickets sold to Sr. citizens = 144
Remaining (400-144) = 256 tickets sold to the rest
Percentage of tickets sold to the Sr. citizens
= (No. of tickets sold to Sr. citizens/No of total tickets) × 100
(144/400)× 100
= 0.36×100
= 36%
Percentage of Tickets sold to the rest
= (No. of tickets sold to the rest/No. of total tickets) × 100
= (216/400)×100
= 0.64×100
= 64%
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
7.
Hrs spent in school = 7 1/2 = (15/2) Hrs
Total Hrs in a day = 24 Hrs
percentage of hrs spent in school per day =[(15/2)/24]×100%
= (15/48)×100%
= 37.25%
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
8.
% composition = (Ratio of tin to copper) × 100
= (3/5)× 100
= 60%
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
9.
Old price = 4₹
New price = 5₹
Change in price = 1₹
4₹ ---> 100%
1₹ -----> (100/4)% = 25%
•°• Required % Increase = 25%
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
10
old price = 240₹
New price = 210₹
change in price = (240 - 210) = 30₹
240₹ ----> 100%
30₹-----> (30×100)/240 = (300/24) = 12.5%
•°• Required % Decrease = 12.5%
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
©#£€®$
:)
Hope it helps
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