Question

please please tell me tge answer of "expand log 19800

Answer 1

19800 = 2*2*2*5*5*3*3*11

log 1980 = log(2*2*2*5*5*3*3*11) = log 2³ + log 5² + log 3² + log 11  =  3log2 + 2log5 + 2log3 + log 11

Answer 2

Answer:

Step-by-step explanation:

$19800 = 2\times2\times2\times5\times5\times3\times3\times11\\\\=2^3\times5^2\times3^2\times11$

Therefore,

$\log 19800 = \log (2^3\times5^2\times3^2\times11)\\\\=\log 2^3+\log5^2+\log 3^2+\log 11\\\\=3\log 2+2\log3 +2\log 5 +\log11$