Math, asked by avanichaudhary200716, 4 months ago

Please plesae answer these questions ita really urgent

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Answered by diyashree
1

Answer:

8) a) proved

8) d) proved

8) c) proved

Step-by-step explanation:

8)a)

(a+b) ^2 - (a-b) ^2

(a^2 +b^2 + 2ab) - (a^2 + b^2 - 2ab)

a^2 + b^2 + 2ab - a^2 - b^2 + 2ab

4ab (+ and - a^2 and b^2 gets cancelled)

8)d)

(a-b) ^2 = a^2 + b^2 - 2ab

(b-a) ^2 = b^2 + a^2 - 2ba

hence the two formulae are same this is also proved

8)c)

(5a^2 - 2b^2)^2 + 40a^2 b^2

25 a^4 + 4 b^4 + 20 a^2 b^2

(5a^2 + 2b^2)^2 [write in (a+b) ^2 formula]

Answered by vipashyana1
3

Answer:

a)(a+b)²-(a-b)²=4ab

(a²+2ab+b²)-(a²-2ab+b²)=4ab

a²+2ab+b²-a²+2ab-b²=4ab

a²-a²+b²-b²+2ab+2ab=4ab

4ab=4ab

L.H.S.=R.H.S.

Hence proved

b)(x²+y²)(x²-y²)-(x²-y²)²=2(x²y²-y^4)

(x²)²-(y²)²-(x^4-2x²y²+y^4)=2(x²y²-y^4)

x^4-y^4-x^4+2x²y²-y^4=2(x²y²-y^4)

x^4-x^4+2x²y²-y^4-y^4=2(x²y²-y^4)

2x²y²-2y^4=2(x²y²-y^4)

2(x²y²-y^4)=2(x²y²-y^4)

L.H.S.=R.H.S.

Hence proved

c)(5a²-2b²)²+40a²b²=(5a²+2b²)²

25a^4-20a²b²+4b^4+40a²b²=(5a²+2b²)²

25a^4-20a²b²+40a²b²+4b^4=(5a²+2b²)²

25a^4+20a²b²+4b^4=(5a²+2b²)²

(5a²+2b²)²=(5a²+2b²)²

L.H.S.=R.H.S.

Hence proved

d)(a-b)²=(b-a)²

a²-2ab+b²=b²-2ab+a²

b²-2ab+a²=b²-2ab+a²

L.H.S.=R.H.S.

Hence proved

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