Question

please poora solve krke bhejna​

Answer 1

Question: A body is moving from d1 = 6i + 4j - 3k to d2 =8i + 2j - 2k under the action of a constant force 2i + 4j - 5k. Find the workdone

Answer:

1 joule

Explanation:

Displacement = d₂ - d₁

        = (8i + 2j - 2k) - (6i + 4j - 3k)

        = (8 - 6)i + (2 - 4)j + (-2 + 3)k

        = 2i - 2j - k

Work done = force x displacement

            = (2i + 4j - 5k) x (2i - 2j - k)

            = (2 x 2) + (4 x (-2)) + (-5 x (-1))

            = 4 - 8 + 5

            = 1

Workdone is 1 joule.

  (however, if that =* means +, answer would be 4-8-5 = - 9 joule)