Question

Please proof it also.​

Answer 1

Answer:

Proof: Given ABCD, let the diagonals AC and BD intersect at E, we must prove that AE ∼ = CE and BE ∼ = DE. The converse is also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram. Theorem: Opposite angles of a parallelogram are congruent to each other.

Answer 2

Answer:

1/2trangle of ACD and 1/2 triangle of ABC