please proof that CP - CV= R
Answers
Answered by
1
let CP be R
suppose CV is zero
now
R - 0=R
hence proved....
suppose CV is zero
now
R - 0=R
hence proved....
Answered by
9
Cp - Cv = R
This is otherwise called Meyer's Relation.
dQ’ = dU + dW
Since the expansion takes place at constant pressure,
dQ ′ = CpdT
∴ CpdT = CvdT + dW …... (2)
Work done, dW = force × distance = = P × A × dx
dW = P dV (since A × dx = dV, change in volume)
∴ CpdT = CvdT + P dV …... (3)
The equation of state of an ideal gas is
PV = RT
Differentiating both the sides
PdV = RdT …... (4)
Substituting equation (4) in (3),
CpdT = CvdT + RdT
Cp = Cv + R
Therefore,
Cp - Cv = R.
Please mark my answer as brainliest.
This is otherwise called Meyer's Relation.
dQ’ = dU + dW
Since the expansion takes place at constant pressure,
dQ ′ = CpdT
∴ CpdT = CvdT + dW …... (2)
Work done, dW = force × distance = = P × A × dx
dW = P dV (since A × dx = dV, change in volume)
∴ CpdT = CvdT + P dV …... (3)
The equation of state of an ideal gas is
PV = RT
Differentiating both the sides
PdV = RdT …... (4)
Substituting equation (4) in (3),
CpdT = CvdT + RdT
Cp = Cv + R
Therefore,
Cp - Cv = R.
Please mark my answer as brainliest.
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