Math, asked by anut0717, 5 hours ago

please prove both sides.​

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Answered by MrNawabzada
2

 \textbf{Given:-}  \:  \frac{25 \times  {2x}^{ - 4} }{ {5}^{ - 2}  \times 10 {x}^{ - 6} }  =  {125x}^{2}

 \textbf{To Prove:-}  \: \frac{25 \times  {2x}^{ - 4} }{ {5}^{ - 2}  \times 10 {x}^{ - 6} }  =  {125x}^{2}

Solution:-

⇒\text{L.H.S}  =  \frac{25 \times  {2x}^{ - 4} }{ {5}^{ - 2} \times 10 \times  {x}^{ - 6}  }  \:  \: \:  \[ \left[  {a}^{ - 1}  =  \frac{1}{a}  \right] \]

⇒ \frac{25 \times 2 {x}^{ - 4}  + 6}{ {5}^{ - 2}  \times 5 \times 2}

⇒ \frac{ {5}^{2}  \times  {x}^{2} }{ {5}^{ - 1} }

⇒ {5}^{2 + 1}  \times  {x}^{2}

⇒125 {x}^{2}

⇒\text{R.H.S}

 \textbf{Hence,}  \:  \frac{25 \times  {2x}^{ - 4} }{ {5}^{ - 2}  \times 10 {x}^{ - 6} }  =  {125x}^{2}

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Answered by barani79530
0

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