Please prove it in copy fast. Its urgent.
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from triangle PAC and PBC
PA=PB ( because it's given that p is equidistant from A and B )
angle C = angle c = 90 degrees (since line l is THE perpendicular bisector of AB)
PC=PC ( common)
hence triangle PAC congruent to triangle PBC by (SAS ) congruency.
hope it helps you :)
zoha2004:
CAN U PLZ MARK IT AS BRAINLIEST
No option is there
Please answer my questions
it'll be possible when someone else answers your question after me
but no one has answered so we'll leave it
bye :)
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