Question

please prove it
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Answer 1

Answer:

Hi ,

LHS = cosA /(1-sinA ) + sinA / ( 1-cosA ) + 1

= [ CosA (1-cosA)+sinA(1-sinA)+(1-sinA)(1-cosA) ]/

(1 -sinA ) ( 1- cosA )

= [ cosA -cos² A + sinA - sin² A +1 -cosA-sinA +sinAcosA ] / ( 1 - sinA ) ( 1 - cosA )

= [ - ( cos²A + sin² A ) + 1 + sinAcosA ] /(1-sinA)(1-cosA)

= [ -1 + 1 + sinAcosA ] / ( 1- sinA ) ( 1- cosA )

= sinAcosA / ( 1 - sinA ) ( 1 - cosA )

= RHS

I hope this helps you.

:)

Step-by-step explanation:

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