Question

Please prove LHS=RHS​

Answer 1

Answer:

cos²a/(cot²a - cos²a) = 3

cos²a/(cos²A/sin²A)-cos²A = 3

cos²a/cos²A[(1/sin²A)-1] = 3

1/[(1/sin²A)-1] = 3

sin²a/(1-sin²a) = 3

sin²a/cos²a = 3

tan²a = 3

tana = √3

tana = tan60°

so,

a = 60° (Ans)

at 60° only it satisfy the above condition .. only one value possible

(Mark as brainlist)