please prove LHS = RHS
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(1+tan²theta)³= 1³+3(1)(tan theta)(1+tan² theta)+tan^6theta
(sec² theta)³= 1+3tan theta + 3tan³theta+ tan^6theta
sec^6theta=1+3tan theta(1+tan²theta)+tan^6theta
sec^6 theta=tan^6 theta+ 3tan²theta sec²theta+1
L.H.S= R.H.S
(sec² theta)³= 1+3tan theta + 3tan³theta+ tan^6theta
sec^6theta=1+3tan theta(1+tan²theta)+tan^6theta
sec^6 theta=tan^6 theta+ 3tan²theta sec²theta+1
L.H.S= R.H.S
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2
sec^6 θ = (sec²θ)³ = (1 + tan²θ)³
(1 + tan²θ)³ = (1)³ + (tan²θ)³ + 3 × 1 × tan²θ (1 + tan²θ)
1 + tan^6 + 3 tan²θ sec²θ
Hence proved.. ;)
(1 + tan²θ)³ = (1)³ + (tan²θ)³ + 3 × 1 × tan²θ (1 + tan²θ)
1 + tan^6 + 3 tan²θ sec²θ
Hence proved.. ;)
wwwakshatongmp34fpw:
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