Question

Please prove that Lhs=Rhs​

Answer 1

hey!!

LHS  =  $\sqrt{x^{p-q}}\cdot \sqrt{x^{q-r}}\cdot \sqrt{x^{r-p}}$

($\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{b}=\sqrt{a\cdot b}$)

= $\sqrt{x^{-q+p}x^{q-r}x^{r-p}}$

=$\sqrt{x^{p-q+q-r+r-p}}$

= $\sqrt{x^0}$

= $\sqrt{1}$

=1

RHS =1

Therefore, LHS = RHS

pls mark as brainliest