Question

Please prove the above that it is equal to (1 + sin)/cos​

Answer 1

Answer:

L.H.S. = tanθ+secθ-1/tanθ-secθ+1

= tanθ+secθ-(sec^2θ-tan^2θ)/tanθ-secθ+1

= (tanθ+secθ)-(secθ+tanθ) (secθ-tanθ)/tanθ-secθ+1

= (secθ+tanθ) (1-secθ+tanθ)/(tanθ-secθ+1)

= secθ+tanθ

= 1/cosθ + sinθ/cosθ

= 1+sinθ/cosθ

= R.H.S

[Proved]