Please prove the above that it is equal to (1 + sin)/cos
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Answer:
L.H.S. = tanθ+secθ-1/tanθ-secθ+1
= tanθ+secθ-(sec^2θ-tan^2θ)/tanθ-secθ+1
= (tanθ+secθ)-(secθ+tanθ) (secθ-tanθ)/tanθ-secθ+1
= (secθ+tanθ) (1-secθ+tanθ)/(tanθ-secθ+1)
= secθ+tanθ
= 1/cosθ + sinθ/cosθ
= 1+sinθ/cosθ
= R.H.S
[Proved]
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