Question

please prove this anybody

Answer 1

Hey mate here is your answer. Look it properly and don't mark as brainliest.

Answer 2

Answer:

1:4

Step-by-step explanation:

Given :-

~~ΔABC :, D, E and F are midpoints of sides AB, BC and CA respectively.

~~BC = EC ||| line joining the midpoints of two sides of a triangle is parallel to third side and half of it.

Proof :-

Hence DF = (1/2) BC ⇒ (DF/BC) = (1/2) → (1) Similarly, (DE/AC) = (1/2)

→ (2) (EF/AB) = (1/2)

→ (3) From (1), (2) and (3) we have

But if in two triangles, sides of one triangle are proportional to the sides of the other triangle, then their corresponding angles are equal and hence the two triangles are similar Hence ΔABC ~ ΔEDF |||[By SSS similarity theorem] Hence :-

area of ΔDEF : area of ΔABC = 1 : 4