Please prove this anyone
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i think this may help you
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Anonymous:
Thank you so much
mention not
nitesh there is no sign between tan²A and tan²B
there is a sign of multiplication
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HELLO DEAR,
-------------Taking L.H.S. , we have------------
---LHS = (1 + tan a tan b)2 + (tan a – tan b)2--
= 1 + tan2a tan2b + 2 tan a tan b + tan2a +
tan2b – 2 tan a tan b
= 1 + tan2a tan2b + tan2a + tan2b
= 1. (1 + tan2b) + tan2a (tan2b + 1)
= (1 + tan2b) + (1 + tan2a)
= sec2b sec2a
= sec2a sec2b
= RHS
I HOPE ITS HELP YOU DEAR,
THANKS
-------------Taking L.H.S. , we have------------
---LHS = (1 + tan a tan b)2 + (tan a – tan b)2--
= 1 + tan2a tan2b + 2 tan a tan b + tan2a +
tan2b – 2 tan a tan b
= 1 + tan2a tan2b + tan2a + tan2b
= 1. (1 + tan2b) + tan2a (tan2b + 1)
= (1 + tan2b) + (1 + tan2a)
= sec2b sec2a
= sec2a sec2b
= RHS
I HOPE ITS HELP YOU DEAR,
THANKS
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