PLEASE PROVE THIS
CLASS 10, CHAPTER-8
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Answer:
1+tan^2A/1+cot^2A=sec^A/cosec^2A=1/cos^2A×sin^2A=sin^2A/cos^2A=tan^2A (proved)
Step-by-step explanation:
again
(1-tanA/1-cotA)^2
=(1-tanA/1-1/tanA)=(tanA-tan^2A/tanA-1)
={tanA(1-tanA)/-(1-tanA)}^2
=(-tanA)^2=tan^2A (proved)
.
. . L.H.S=R.H.S (proved)
Answered by
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Step-by-step explanation:
so in first one 1+tan^2 A=sec^2 A and also 1+cot^2 A=cosec^2 A put these values we get
sin^2 A/cos^2 A= tan^2 A
now in second one simplify we get
(1-tan A)^2=sec^2 A -2tan A=1-sin2A/cos^2 A
(1-cot A)^2=cosec^2 A -2cotA=1-sin2A/sin^2 A
solving further we get
sin^2A/cos^2A=tan^2A
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