Math, asked by Vansh080605, 5 months ago

PLEASE PROVE THIS
CLASS 10, CHAPTER-8

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Answered by ib6959395
0

Answer:

1+tan^2A/1+cot^2A=sec^A/cosec^2A=1/cos^2A×sin^2A=sin^2A/cos^2A=tan^2A (proved)

Step-by-step explanation:

again

(1-tanA/1-cotA)^2

=(1-tanA/1-1/tanA)=(tanA-tan^2A/tanA-1)

={tanA(1-tanA)/-(1-tanA)}^2

=(-tanA)^2=tan^2A (proved)

.

. . L.H.S=R.H.S (proved)

Answered by Anonymous
0

Step-by-step explanation:

so in first one 1+tan^2 A=sec^2 A and also 1+cot^2 A=cosec^2 A put these values we get

sin^2 A/cos^2 A= tan^2 A

now in second one simplify we get

(1-tan A)^2=sec^2 A -2tan A=1-sin2A/cos^2 A

(1-cot A)^2=cosec^2 A -2cotA=1-sin2A/sin^2 A

solving further we get

sin^2A/cos^2A=tan^2A

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