Question

please Prove this please


$\sqrt{ \frac{1 + \sin( \alpha ) }{1 - \sin( \alpha ) } } = \sec( \alpha ) + \tan( \alpha )$






What is your problem giving answers only for points try to help others


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i really need help
please help





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Answer 1

Step-by-step explanation

Answer 2

Answer:

$\huge\underbrace\mathcal\blue{Answer}$

In a given triangle ABC, right-angled at B = ∠B = 90°

Given: AB = 24 cm and BC = 7 cm

That means, AC = Hypotenuse

According to the Pythagoras Theorem,

In a right-angled triangle, the squares of the hypotenuse side are equal to the sum of the squares of the other two sides.

By applying Pythagoras theorem, we get

AC2 = AB2 + BC2

AC2 = (24)2 + 72

AC2 = (576 + 49)

AC2 = 625 cm2

Therefore, AC = 25 cm