Please proved it immediately
Attachments:
Answers
Answered by
1
Answer:
W.K.T,
sin A sin B + cos A cos B = cos(A-B)
sin (nA+A) sin(nA+2A) + cos(nA+A) cos(nA+2A) = cos (nA+A-nA-2A) = cos (-A) = cos A
Hence proved
Hope it helps you
Answered by
1
Answer:
Here is your proof. Hope you liked it!
Step-by-step explanation:
Taking Left hand side,
We know that,
Cos ( A - B ) = Cos A . Cos B + Sin A . Sin B
A = ( n + 1 ) A
B = ( n + 2 ) A
So, = Cos [( n + 1 ) A - ( n + 2 ) A )
= Cos ( n + A - n A - 2 A )
= Cos ( - x )
= Cos x { Since cos(-x) = Cos x }
Hence proved.
LHS = RHS
Similar questions