Math, asked by studentnick, 8 months ago

please provide correct answer​

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Answered by AadityaSingh01
1

Answer:

i) 4\sqrt{28}+ 4\sqrt{7}/3   and   ii) 3\sqrt{2} + 2\sqrt{3}

Step-by-step explanation:

i) 28/\sqrt{28} - \sqrt{7}  

= 28/\sqrt{28} - \sqrt{7} * \sqrt{28} + \sqrt{7}/\sqrt{28} + \sqrt{7}

= 28\sqrt{28}+ 28\sqrt{7}/28-7

= 28(\sqrt{28} + \sqrt{7})/21

= 4\sqrt{28}+ 4\sqrt{7}/3

ii) 6/3\sqrt{2} - 2\sqrt{3}

= 6/3\sqrt{2} - 2\sqrt{3} * 3\sqrt{2} + 2\sqrt{3}/3\sqrt{2} + 2\sqrt{3}

= 6(3\sqrt{2} + 2\sqrt{3})/18-12

= 6(3\sqrt{2} + 2\sqrt{3})/6

= 3\sqrt{2} + 2\sqrt{3}

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