Question

please provide me with the solution of this question​

Answer 1

Answer:

8

Step-by-step explanation:

a= 2i +2j+3k

b=-i +2j+k

c=3i+j

a+λb = (2-λ)i + (2+2λ)j + (3+λ)k

a+λb is perpendicular to c

then, (a+λb).c = 0

(2-λ)i + (2+2λ)j + (3+λ)k . [3i + j] = 0

3(2-λ) + (2+2λ)=0

8-λ=0

λ=8