Please provide PROPER "SOLUTION" for the given question. (No spam)
(The answer is 1580 but I'm getting 1680, probably I did something wrong in the case of B)
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Explanation:
The net tension in the rope is equal in magnitude to sum of the three forces or apparent weights of A, B and C, which can be calculated by multiplying their weights with their net accelerations
i.e.
F1 = W1 = m1×a1 = 60×(10+2) = 720 N
similarly
F3 = W3 = m3×a3 = 40×(10-1) = 360 N
but in case of B the acceleration is not given hece we would prefer the default acceleration = g = 10 m/s2 hence .:
F3 = m3×a3 = 50×10 = 500 N
THUS the net force = F1+F2+F3 = 720+360+500 = 1580 N
NOTE .: As the body accelerates downward the gravitational force on it decreases thus the net force is the product of its mass with the acceleration *g-a* and vice versa.
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