Question

please pura answer karke dena​

Answer 1

Answer:

Explanation:

now r1 and r3 are connected end to end

∴they are in series.

Rs= R1+R2

Rs=8kΩ

and rs and R2 are in Parallel

Rp= $\frac{RsxR2}{Rs+R2}$

Rp=$\frac{10kx8k}{10k+8k}$

Rp=$\frac{80000}{18000}$

Rp=$\frac{80}{18\\}$

Rp=4.44Ω