Question

Please question 15 father's age is three times the sum of age of two children . After 5 years , his age will be twice the sum of ages of two children . Find age of father

Answer 1

Answer:

HEY MATE .........

HERE'S YOUR ANSWER

Step-by-step explanation:

Let the age of the sons be x and y.

Given that Father’s age is three times the age of his two sons.

Therefore, present age of father is 3(x+y)

Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

3(x+y)+5 = 2(x+5+y+5)

3x+3y+5 = 2x+10+2y+10

3x+3y+5 = 2x+2y+20

3x-2x+3y-2y = 20–5

x+y = 15

Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

Thus the age of the father is 45.

Answer 2

Answer:

let 1st child age=x

let 2nd child also be=x

so, father's age=3(x+x)

after five years, fathers age=3(x+x) +5

two children age=x+5+x+5

=2x+10

according to the question,

3(x+x) +5=2(2x+10)

3x+3x+5=4x+20

6x+5=4x+20

6x=4x+15

2x=15

x=7.5

So fathers age=3(7.5+7.5)

=3×15

=45

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