Question

please question my answer​

Answer 1

$\huge{\texttt {\orange {Solution}}}$

Given :-

mass of the bullet (m₁) = 0.02 kg

mass of the gun (m₂) = 7.5 kg

Velocity of the bullet (v₁) = 200 m/s

and the speed of the gun (v₂) = ?

So,

the recoil velocity of the gun

Now,

According to the law of conservation of momentum,

The total momentum of system after firing will be equal to total momentum of system before firing

⇒ m₁v₁ + m₂v₂ = 0

[ ∴ as initial velocities of the gun and bullet is 0 before firing ]

⇒ 0.02 × 200 + 7.5 × v₂ = 0

⇒ 4 + 7.5 × v₂ = 0

⇒ 7.5 × v₂ = -4

⇒ v₂ = 0.53 m/s

Hence,

The recoil velocity of gun is 0.53 m/s

Answer 2

Answer:

-0.533

Explanation: