Question

please quick answer q. 1

Answer 1

f(x) =
${x}^{4} + {x}^{3} - 3 {x}^{2} + 3x + 1$

find Zero of polynomial
p(x)
$x - 1$
$x - 1 = 0$
$x = 1$
Using Remainder theorem

f(1) =
${x}^{4} + {x}^{3} - 3 {x}^{2} + 3x + 1$
=>
$1 + 1 - 3 + 3 + 1$
=>
$3$
Therefore 3 is Remainder when f(x) is divided by p(x).