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Explanation:
i) fe+2hcl=>Fecl2+h2
- Molecular mass of iron=56
n=7/56=1/8mol
1/8mol of Fe forms 1/8mol of FeCl2
(1/8)*(56+2*35.5)
( 1/8)*(56+71)
(1/8)*127
15.8g
II) 1mol of h2 from 2mol of hcl and 1mol of Fe
n=10/2=5moles
so 5moles of Fe needed
=5*56
=280g.
9)neutralisation means
N1V1=N2V2
n1*M1V1=n2*M2V2
1*M1*50=1*2*15
M1=30/50
I) M1=3/5=0.6mol/dm3
II)M1=(3/5)*molar mass g/dm3
M1=3/5*17
M1=51/5=10.2g/dm3
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