please quickly solve this question .
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Step-by-step explanation:
tan³Q + cot³Q -2 = 50
tan³Q + 1/tan³Q -2 = 50
(2-√3)³ + 1/ (2-√3)³ = 50
(8-3√3) + 1/(8-3√3) = 50
{(8-3√3)²+1}/(8-3√3) = 50
(92 - 48√3)/(8-3√3) = 50
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