Question

please rationalize...........


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Answer 1

the above one is the solution

Answer 2

$\mathfrak{AnSwEr}$

$\sf{\frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} ... + \frac{1}{\sqrt{8} + \sqrt{9}}}$

On rationalizing it, we get :

$\sf{\sqrt{3} - \sqrt{2} - \sqrt{3} + \sqrt{4} - \sqrt{4} ... + \sqrt{9}}$

=》 $\sf{3 - \sqrt{2}}$