Please read this and explain me the reaction taking place at the anode.
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Copper sulphate dissociate to form copper 2+ iron and sulphate 2- ion.
at cathode the Cu 2+ iron gets 2 electrons and get deposited on the cathode .
this creates a vacant space in the solution for copper 2+ ion.
to fill this vacant space the copper anode gradually loses two electrons to take its place
at cathode the Cu 2+ iron gets 2 electrons and get deposited on the cathode .
this creates a vacant space in the solution for copper 2+ ion.
to fill this vacant space the copper anode gradually loses two electrons to take its place
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Anode is gone under oxidation
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