Question

Please refer to above attachment

From expansion chapter...

STEP BY STEP EXPLANATION REQUIRED ​

Answer 1

Answer:

(x+y)^2=64,(x-y)^2=16

Step-by-step explanation:

under root goes to right side....then...

x+y=8.......eq.1

x-y=4......eq.2

from eq..2,x=4+y... substitute in eq...1

from eq...1 ..,4+y+y=8

2y=8-4

y=4/2

y=2....sub...in eq 1 or 2

u will get x value=6..

xy=6×2=12...

hope this helps you...

Answer 2

ǫᴜᴇsᴛɪᴏɴ :-

If ( x + y) ² = 64 and ( x - y) ² = 16 , find the value of xy.

ɢɪᴠᴇɴ :-

• ( x + y)² = 64. ----(1)

• ( x - y) ² = 16. ----(2)

ᴛᴏ ғɪɴᴅ :-

• Value of xy

sᴏʟᴜᴛɪᴏɴ :-

Now,

Square root both sides of eq (1) and (2) , we get

Equation (1)

➨ ( x + y) ² = 64

➨ ( x + y) = √64

➨ ( x + y) = 8. ---(3)

Equation (2)

➨ ( x - y)² = 16

➨ ( x - y) = √16

➨ ( x - y) = 4. --(4)

On adding (3) and (4) , We get,

➨ ( x + y) + ( x - y) = 8 + 4

➨ 2x = 12

➨ x = 12/2

➨ x = 6

Put x = 6 in (1) , We get,

➨ x + y = 8

➨ 6 + y = 8

➨ y = 8 - 6

➨ y = 2

Hence,

• ➲ Value of xy = 6 × 2 = 12