Question

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Answer 1

Step-by-step explanation:

Here is Answer....,....

Triangle ADB= 90°

(angle subtended by diameter on circumference)

ZC + 20° +30° = 180°

ZC=130°

In quadrilateral ABCD

• ⇒ ZC+ ZA = 180°

• ⇒ ZA 180-ZC

(diagonally opposite angles in cyclic quadr.)

⇒ ZA 180 - 130 = 50°

⇒ ZDAB = 50°

In Triangle ADB

ZDAB+ ZADB + ZDBA = 180°

50° +90° + ZDBA = 180°

In quadrilateral ABDE

ZDBA = 40°

ZB+ ZE=180° (diagonally opposite angles in cyclic quadrtrlal)

ZE=180° - 40° = 140°

• ZAED = 140°

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Answer 2

Step-by-step explanation:

angle DBA =40°

angle DAB =50°

angle AED =140°

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