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Answered by
1
Step-by-step explanation:
Here is Answer....,....
Triangle ADB= 90°
(angle subtended by diameter on circumference)
ZC + 20° +30° = 180°
ZC=130°
In quadrilateral ABCD
- ⇒ ZC+ ZA = 180°
- ⇒ ZA 180-ZC
(diagonally opposite angles in cyclic quadr.)
⇒ ZA 180 - 130 = 50°
⇒ ZDAB = 50°
In Triangle ADB
ZDAB+ ZADB + ZDBA = 180°
50° +90° + ZDBA = 180°
In quadrilateral ABDE
ZDBA = 40°
ZB+ ZE=180° (diagonally opposite angles in cyclic quadrtrlal)
ZE=180° - 40° = 140°
- ZAED = 140°
Answered by
1
Step-by-step explanation:
angle DBA =40°
angle DAB =50°
angle AED =140°
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