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Explanation:
from equ a motion
s=ut+0.5gt²
s is the distance coveredU is intial velocity ,t is time and g is acceleration due to gravity since ball is dropped u =0
so we get
s=0.5*9.8*3.34²
=54.66m
v=u+gt
v is the final velocity
v=9.8*3.34
=32.73m/s
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