Question

Please refer to the attachment ( std 9 geometry) ​

Answer 1

Answer:

[Given] PR = 20 cm and QS = 48 cm [Given]

∴ PT = (1/2) PR [Diagonals of a rhombus bisect each other]

= (1/2) x 20 = 10 cm

Also,

QT = QS [Diagonals of a rhombus bisect each other]

= (1/2) x 48 = 24 cm

Answer 2

Step-by-step explanation:

Diagonals of a rhombus bisect each other at right angles.

PR=20cm

⇒PQ=

2

1

PR=

2

1

×20=10cm

Similarly, QS=48cm

⇒QO=

2

1

SQ=

2

1

×48=24cm

In ΔPOQ, applying Pythagoras theorem,

OQ

2

+QP

2

=PQ

2

⇒24

2

+10

2

=PQ

2

⇒PQ

2

=576+100

⇒PQ

2

=676

⇒PQ=26cm