Question

please refer to the image attached with it​

Answer 1

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\underline{\underline{\huge\mathcal{\bf{\boxed{\huge\mathcal{~~QUESTION~~}}}}}}}$

see in the attachment

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\underline{\underline{\huge\mathcal{\bf{\boxed{\huge\mathcal{!!ANSWER!!}}}}}}}$

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\large\mathcal{\bf{\boxed{\large\mathcal{option 4}}}}}$

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

u=2i+3j

a=0.3i+0.2j

t=10sec

now ....

v=u+at

v=(2i+3j)+10(0.3i+0.2j)=5i+5j

therefore magnitude is

$\sqrt{5 {}^{2} + 5 {}^{2} } \\ = \sqrt{50} \\ = 5 \sqrt{2}$

option (4)

$\huge\mathcal\green{\underline{hope\:\: this\:\: helps\:\: you}}$

Answer 2

Answer:

Explanation:

The option 4