Math, asked by madhuritalakal, 1 month ago

please say answer guys ​

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Answers

Answered by yogeshbhuyal780
1

Answer:

please say answer guys

up is answer best of luck

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Answered by borate71
1

Answer:

I hope this is helpful to you! :)

Step-by-step explanation:

1)

 {x}^{2}  + 7x + 12 = 0

 {x}^{2}  + 3x + 4x + 12 = 0

x(x + 3) + 4(x + 3) = 0

(x + 3)(x + 4) = 0

 \huge \blue {x =  - 3 \:  \: or \: x =  - 4}

2)

 {c}^{2}   -  18c + 65 = 0

 {c}^{2}  - 13c - 5c + 65 = 0

c(c - 13) - 5(c - 13) = 0

(c - 5)(c - 13) = 0

 \huge \pink {c = 5 \:  \: or \: c = 13}

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