Math, asked by deepashrias, 1 month ago

please say answer I will mark brainliest​

Attachments:

Answers

Answered by cjsdnjvmmmmmmmmmmmm
0

Answer:

Let Ashimas’s present age = A years

According to the first given condition i.e.,lochan is twice as old as Ashima.

Therefore, S = 2A …(i)

Given, if six years is subtracted from Ashima’s age and four years added to lochan s age, then lochan will be four times that of Ashima’s age.

Therefore,

4×(A–6)=S+4

⇒4A–24=S+4

⇒4A–S=28 …(ii)

Now, putting value of S from equation (i) in equation (ii), we get

4A –2A = 28

⇒2A=28 ⇒A=14

Thus, Ashima’s present age is 14 years.

Putting value of A in equation (i), we have

S=2×14=28years

lochans present age is 28 years.

Ashima’s age 2 years ago = (14 – 2) years = 12 years

lochan’s age 2 years ago = (28 – 2) years = 26 years

Sum of Ashima’s age and lochan  ’s age two years ago = (12 + 26) years = 38 years

So, the correct answer is “38 years''

Similar questions