Math, asked by princepanjnathiya9, 1 month ago

please say fast please​

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Answered by shashikirantripathi1
1

Answer:

in this picture there are four questions

which questions answer do you need

Answered by ManishShah98
2

\small\red{\boxed{Question  =  }} \:  \underline{rationalize} \: \small\red{\boxed{ \frac{1}{ \sqrt{7} -  \sqrt{6}  } }.} \\  \\ \small\orange{\underline{ \underline{solution}:  - }} \\  \\  \color{blue} =  \frac{1}{ \sqrt{7}  -  \sqrt{6} }  \\   \\ \color{blue} =\frac{1 \times \sqrt{7}  +  \sqrt{6}  }{ \sqrt{7}  -  \sqrt{6}  \times  \sqrt{7}  +  \sqrt{6} } \\  \\ \color{blue} = \frac{ \sqrt{7} +  \sqrt{6}  }{( { \sqrt{7} )}^{2} - ( { \sqrt{6}) }^{2}  }  \\  \\ \color{blue} = \frac{ \sqrt{7}  +  \sqrt{6} }{7 - 6}  \\  \\ \color{blue} = \frac{ \sqrt{7}  +  \sqrt{6} }{1}  \\  \\ \color{green} = \sqrt{7}  +  \sqrt{6}  \:  \:  \:  \:  \: answer \\  \\  \\ \small\red{\boxed{Question  =  }}  \: \:  \underline{find \: the \: value \: of \: polynomial } \\ \small\red{\boxed{5 {x}^{2} - 4x + 3 }} \:  \:\underline{if}  \:  \: \small\red{\boxed{x =  - 1}} \\  \\ \small\orange{\underline{ \underline{solution}:  - }} \\  \\  \color{blue} p(x) = 5 {x}^{2}  - 4x + 3 \\  \\ \color{blue}p( - 1) = 5( - 1)  {}^{2}  - 4( - 1) + 3 \\  \\ \color{blue} = 5(1) + 4 + 3 \\  \\ \color{blue} = 5 + 7 \\  \\ \color{green} = 12 \:  \:  \: answer \\  \\  \\ \small\pink{\boxed{\boxed{it's ᭄亗 乄 MꫝղᎥនh 乄 亗✯❤࿐}}}

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