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question
Find area of the above diagram

Where ABCF is a square whose side is 18 cm.

And Trapezium CDEF whose height is 6 cm, and two sides are 7 cm and 18 cm ​

Answer 1

Given the figure is made up of Square of trapezium

We have to find the Area of diagram

SOLUTION:-

If we find the area of square as well area of trapezium this area sum gives the are of above diagram

$\bigstar \underline{\boxed{ \mathfrak{{Area}_{(Square)} = a^2}}}$

• a denotes side of square

$\bigstar \underline{\boxed{ \mathfrak{{Area}_{(Trapezium)} = a+b/2\times h}}}$

• a, b are the bases
• h is the height of trapezium

Area of square = a²

a = 18cm

Area of square = (18)²

= 324 cm²

Area of square = 324cm²

Area of trapezium = a+b/2 × h

Given bases are 7cm and 18cm

Height = 6cm

${Area\: of \: trapezium} = \dfrac{a+b}{2} \times h$

$\dfrac{7+18}{2} \times 6$

= 25 × 3

= 75cm²

Area of trapezium = 75cm²

Area of given diagram = Area of square +Area of trapezium

= 324cm² + 75cm²

= 399cm²

So, area of given diagram is 399cm²

Answer 2

Answer:

399 cm²

Step-by-step explanation:

The whole diagram is made up of one trapezium (CDEF) and one square (ABCF)

To find the area of whole diagram. First we have to find the area of trapezium and area of square. Then add both areas.

Area of square = Side × Side

= 18 cm × 18 cm

= 324 cm²

Area of square = 324 cm²

Area of Trapezium = (sum of two parallel sides)/2 × height

= (7 cm + 18 cm)/2 × 6 cm

= (25 cm)/2 × 6 cm

= 25 cm × 6 cm / 2

= 150 cm² / 2

= 75 cm²

Area of trapezium = 75 cm²

Total area of diagram = Area of square + area of trapezium

= 324 cm² + 75 cm²

= 399 cm²

Hope it helps.