Math, asked by adhikariambika2064, 2 months ago

please say me the answer of the question​

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Answered by osikachaudhary5
1

Answer:

a. 3a+9 ,a^2-9

=1st exp =3a+9

=3(a+3)

2nd exp =a^2-9

=a^2-3^2

=(a-3)(a+3)

l.c.m=(a+3)(a-3)

b. a^2+a,a^2-1

1st exp =a(a+1)

2nd exp =a^2-1

=a^2-1^2

=(a-1)(a+1)

l.c.m =a(a+1)(a-1)

c. x^2-25,x^2y-5xy

1st exp =x^2-25

=x^2-5^2

=(x-5)(x+5)

2nd exp =x^2y-5xy

=xy(x-5)

l.c.m =xy(x-5)(x+5)

d. 1st exp =4x^3-9x

=x(4x^2-9)

=x(2x^2)-(3^2)

=x(2x-3)(2x+3)

2nd exp = 10x^2-15x

=5x(2x-3)

l .c.m =x.5x(2x-3)(2x+3)

hope its helpful

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