Question

please say solution fastly​

Answer 1

Answer:

answer in the attachment

Answer 2

Answer:

15 cm and 20 cm

Step-by-step explanation:

Hypotenuse of triangle = 25cm

Difference between lengths of other two sides = 5cm

Let second side (base) = x

third side – second side = 5

So we have,

third side (perpendicular)= 5 +x

We know ,

according to Pythagoras theorem, the square of hypotenuse is equal to sum of squares of other two sides of triangle.

So (hypotenuse)² = (perpendicular)² + (base)²

(25)² = (5+x)² + (x)²

625 = 25 + x²+ 10x + x²

2x² + 10x +25 – 625 = 0

2x² + 10x – 600 = 0

x² + 5x – 300 = 0

x² – 15x + 20x – 300 = 0

x ( x–15) + 20 (x–15) = 0

(x– 15) (x+20) = 0

thus x= 15 , –20

as length cannot be negative

we take x= 15

and third side = 15+5 = 20

So required sides are 15cm and 20cm