Math, asked by anuradhakancharla8, 8 months ago

please say the answer ​

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Answered by Anonymous
1

 \huge\mathbb\red{Answer:-}

4(3x + 4y)^2+12(3x + 4y)(2x + 5y) + 9(2x + 5y)^2

= [2(3x + 4y)]^2+2×2(3x + 4y)×3(2x + 5y) + [3(2x + 5y)]^2

= [2(3x + 4y) + 3(2x + 5y)]^2

= (6x + 8y + 6x + 15y)^2

= (12x + 23y)^2

___________♡♡

Answered by Anonymous
0

4(3x + 4y)^2

+12(3x + 4y)(2x + 5y) + 9(2x + 5y)^2

= [2(3x + 4y)]^2

+2×2(3x + 4y)×3(2x + 5y) + [3(2x + 5y)]^2

= [2(3x + 4y) + 3(2x + 5y)]^2

= (6x + 8y + 6x + 15y)^2

= (12x + 23y)^2

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