Math, asked by bhavidhan1234, 11 hours ago

please say the answer​

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Answered by learner2929
0

cosecθ + cotθ = k

cosecθ + cosθ/sinθ = k

1/sinθ + cosθ/sinθ = k

(1+cosθ)/sinθ = k

1 + cosθ = k sinθ. --1

On squaring both sides

(1 + cosθ)^2 = (k sinθ)^2

1 + 2cosθ + cos^2θ = k^2sin^2θ

1 + cosθ = k^2 (1 + sinθ) (1 - sinθ)

1 + cosθ = k^2 (1 - cosθ)

1 + cosθ = k^2 - k^2cosθ

(1 + k^2) cosθ = 1 - k^2

cosθ = (1 - k^2)/(1 + k^2)

Hence proved.

Answered by IqBroly
0

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