Question

please say the answer ​with steps then i will mark you as brainliest

Answer 1

after some simplifications ,

$\bf25 \times {t}^{ - 4} \times {5}^{3} \times {10}^{ - 1} \times {t}^{8} = 0$

$\bf25 \times {t}^{4} \times 125 \times {10}^{ - 1} = 0$

$\bf25 \times {t}^{4} \times 12.5 = 0$

$\bf {t}^{4} = {25}^{ - 1} \times {12.5}^{ - 1} = {5}^{(2 - 1)} \times 0.08$

$\bf {t}^{4} = 5 \times 0.08 = 0.4$

$\bf {t}^{2} = \sqrt{0.4} = 0.63$

$\bf t = \sqrt{0.63} = 0.79$

• the value of t is 0.79