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answer of question 14 is 130degrees
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question number 12
given : AB is parallel to CD
find : find the value of x
construction: draw a line parallel to ab and cd
solution :
MEB + ABE = 180 (angles on the same side of transversal )
MEB + 130 = 180
MEB = 180-130
MEB = 50
NEC + ECD = 180 (angles on the same side of transversal )
NEC + 125 = 180
NEC = 180-125
NEC = 55
MEB + BEC + CEN = 180 (linear pair )
50 + x + 55 = 180
105 + x = 180
x = 180-105
x = 75
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answer of 13 question is 130
100+3x+5x=180
8x=180-80
x=80/8
x=10
put in 3x =3 multiplied by 10 = 30
angle AOC = 30+100= 130
given : AB is parallel to CD
find : find the value of x
construction: draw a line parallel to ab and cd
solution :
MEB + ABE = 180 (angles on the same side of transversal )
MEB + 130 = 180
MEB = 180-130
MEB = 50
NEC + ECD = 180 (angles on the same side of transversal )
NEC + 125 = 180
NEC = 180-125
NEC = 55
MEB + BEC + CEN = 180 (linear pair )
50 + x + 55 = 180
105 + x = 180
x = 180-105
x = 75
if you find my answer effective just follow me and click the thanks button
answer of 13 question is 130
100+3x+5x=180
8x=180-80
x=80/8
x=10
put in 3x =3 multiplied by 10 = 30
angle AOC = 30+100= 130
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