Question

please say this solution ​

Answer 1

$\frac{1}{ {x}^{2} - 25 } = \frac{1}{k} ( \frac{1}{x - 5} - \frac{1}{x + 5} )$

$\frac{1}{ {x}^{2} - 25} = \frac{1}{k} ( \frac{ (x + 5) - (x - 5)} { {x}^{2} - 25 } )$

$1 = \frac{x + 5 - x + 5 }{k}$

$k = 10$