Question

please say what is the answer​

Answer 1

Step by step explanation:-

$\\\\{\rightsquigarrow\sf \cfrac{ {a }^{2} - 5ab}{ {a}^{2} - 6ab + 5 {b}^{2} } \times \cfrac{ {a}^{2} - {b}^{2} }{ {a}^{2} + ab } }$

${\rightsquigarrow\sf \cfrac{ a({a }^{} - 5b)}{ {a}^{2} - 5ab - ab + 5 {b}^{2} } \times \cfrac{ (a + b)(a - b) }{ a({a}^{} + b) } }$

${\rightsquigarrow{\sf \cfrac{ a({a }^{} - 5b)}{a( {a}^{} - 5b) - b ( a - 5 {b}^{}) } \times \cfrac{ \xcancel{ (a + b)}(a - b) }{ a \: \: \xcancel{({a}^{} + b) }} }}$

$~~~~~~~~~~~{\rightsquigarrow\sf \cfrac{ a({a }^{} - 5b)}{ (a - 5b)(a - b) } \times \cfrac{a - b }{ a} }$

$~~~~~~~~~~~~~~{\rightsquigarrow\sf \cfrac{a \: \: \xcancel{ ({a }^{} - 5b)}}{ \xcancel{(a - 5b)}(a - b) } \times \cfrac{a - b }{ a} }$

$~~~~~~~~~~~~~~~~~\sf\rightsquigarrow \dfrac{a}{a - b} \times \cfrac{a - b}{a}$

$~~~~~~~~~~~~~~~~~~~~~\sf\rightsquigarrow \dfrac{a(a - b)}{a(a - b)}$

$~~~~~~~~~~~~~~~~~~~~~~\sf\rightsquigarrow \dfrac{\xcancel{a(a - b)}}{\xcancel{a(a - b)}}$

$~~~~~~~~~~~~~~~~~~~~~~~~\underbrace{\underline{\boxed{\mathfrak{\cancel{Ans}}=~1}}}$

$\\\sf The~Value~of \Bigg[ {\sf \cfrac{ {a }^{2} - 5ab}{ {a}^{2} - 6ab + 5 {b}^{2} } \times \cfrac{ {a}^{2} - {b}^{2} }{ {a}^{2} + ab } }\Bigg] \: is \: \boxed{ \bf\green1}$

More to Know

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\sf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\sf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\sf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8)\sf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\\end{minipage}}$

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